Question

a ball of mass M moving with speed v collides perfectly inelastically with another ball of mass m at rest v. the magmnitud of impulse imparted to the first ball is..

1) Mv

2) mv

3) Mm/(M+m) *v

4) M2 v/(M+m)

Answer 1

Since, the collision is perfectly inelastic, both masses will stick together after the collision.

Let V be the velocity of the combined mass. Therefore,




Impulse imparted to the first ball will be  MV = Mmv/m+M option. (3)

Answer 2

Answer is 3

Explanation:Get known that in inelastic collison momentum of the particles is conserved.And after collison the velocities of both bodies become same.

Impulse is change in momentum.

By conservation of momentum for both particles,

Mv= (M+m)ω

Let ω be the common velocity of the objects after collison.

Therefore,

ω=(Mv)/(M+m)

SO CHANGE IN MOMENTUM OF FIRST PARTICLE(IMPULSE)=Mω-Mv

Substitute the value of ω found and Holla ur done then.......yes