Question

A ball of mass m1 and another ball of mass m2, are dropped from equal height. If time taken by the ballsare
t1 and t2 respectively, then –

(A)t1= t2/2
(B) t1=t2
(c)t1=4t2
(d)t1=t2/4​

Answer 1

Answer:

t1=t2

Explanation:

acceleration of both objects doesn't depend on their masses. mg=ma, so g=a

so velocity acquired by both are equal therefore the time taken by is equal.