Question

A ball of mass o.4kg is accelerated uniformly
from a velocity of 5m/s to 8m/s in 6 seconds-
The force acting on the object is

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Answer 1

Answer:

0.2N is the force acting on the body

Answer 2

hi mate here is your answer -

F = ma

F = m ( v - u ) /t

Mass - 0.4kg

initial velocity ( u ) - 5 m/s

final velocity ( v ) - 8 m/s

Now, using formula -

F = ma

F = m ( v - u )/t

F = 0.4 kg ( 8 m/s - 5 m/s )/6 s

F = 0.4 kg × 3 m/s / 6s

F = 0.4kg × 1/2 m/s

F = 0.4/2 kgm/s

F = 1/5 kgm/s

F = 0.2 kgm/s

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