Question

A ball rolling down a hill at 4.0 m/s accelerates at 2.0 m/s2. What is its velocity 5.0s later?

Answer 1

we need to use the kinematic equation involving quantities of interest: initial velocity u, final velocity v, acceleration and time

so we use formula

v= u+at

v= 4+ 2*5

v= 4+10

v= 14m/sec

Answer 2

Hey there!
Here is you answer...

u = 4.0 ms^-1
a = 2.0 ms^-2
t = 5.0s

v = u + at

= 4.0 + 2.0 × 5.0

= 4 + 10

= 14ms^-1 ans.

Hope, it helps you...

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