Question

a ball rolls off a table and hits the floor at 5m/s. What is the height of the table

Answer 1

hey user here is Answer

Solution

according to question

given that

v=5 m/s

u=0

g=10

h=?

using this formula

{v}^{2} = {u}^{2} + 2gh

${5}^{2} = {0}^{2} + 2 \times 10 \times h \\ \\ 25 = 20h \\ \\ h = \frac{25}{1</u></em></p><p><em><u>2</u></em><em><u>0} \\ </u></em></p><p><em><u>\\ h = </u></em><em><u>5</u></em><em><u>/</u></em><em><u>4</u></em><em><u> </u></em></p><p></p><p><em><u>h</u></em><em><u>=</u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em><em><u>5</u></em><em><u> m \: </u></em></p><p><em><u>\: \: answer$

Answer 2

Explanation:

apply the formula v(square)=u(square)+2as

where u =0,v=5 ,a=g=10, h=S

so

putting the values in the formulae we get

25=0+2.10.h

25=20h

25÷20=h

h=1.25m (and)