A ball rolls off a table with a velocity of 3.2 m/s. The table is 1.5 m high. a. When does the ball hit the floor? b. How far from the base of the table does the ball travel? c. With what velocity does the ball hit the floor?
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Answer:
Using h=
2
1
gt
2
, we have
h
AB
=
2
1
gt
AC
2
or t
AC
=
g
2h
AB
=
9.8
2×4
=0.9s
Further, BC=vt
AC
.
or v=
t
AC
BC
=
0.9
5.0
=5.55m/s
solution
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