A ball starts from rest and rolls down 16m down an inclined plane in 4s. 1] What is the acceleration of the ball. 2] What is the velocity of the ball at the bottom of the incline .
Answers
Answered by
224
given,
u=0m/s
s=16m
t=4sec
1]
s=ut+1/2at^2
16 = o × t + 1/2 × a × 4 × 4
16 = 8a
a = 2 m/s^2
2]
v=u+at
v=0+2×4
v=8m/s
HOPE THIS WILL HELP U
u=0m/s
s=16m
t=4sec
1]
s=ut+1/2at^2
16 = o × t + 1/2 × a × 4 × 4
16 = 8a
a = 2 m/s^2
2]
v=u+at
v=0+2×4
v=8m/s
HOPE THIS WILL HELP U
Answered by
39
Velocity=distance/time V=16/4 V=4m/s Acceleration=final velocity -initial velocity/time a=4-0/4 a=4/4 a=1m/s2
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