Question

a ball starts rolling over floor with initial velocity 0.2m/s. due to frictional force its velocity decreases at a rate of 0.01m/s2. Calculate the time after which the ball will come to rest.
Plz answer..

Answer 1

u=.2m/s
a=-0.01
v equal0
0=.2-0.01t
-0.2=-0.01t
-0.2/-0.01=t
20=t
t equal 20sec