Question

a ball throw a point velocity v and angle theta .at same point a person start run at same instant with velocity v/2 so man so the theta is??​

Answer 1

Answer:

horizontal distance covered by the ball= horizontal range= (hope u know the formula) R=[V2sin2(theta)]/g

time taken by the ball to reach the ground=T=2Vsin(theta)/g

note;] remember that time taken by the person to reach the spot and time taken

         by the ball to reach the ground(same spot)..is THE SAME;

time taken by the person to reach the spot= time taken by the ball..

    distance/speed (man)          =        2v sin theta/g  [ball]

    range/speed[man]               =             '''' '''' 

   ( V2sin 2 theta/g) / v/2        =              '''' ''''

       things cancel out in the equation and finally u get     sin (theta) = sin 2 (theta)                                                          

this can happen if theta = 00 ...............................which is not possible

...therefore  2 theta= 180-theta.........by trigonometry

                    3 theta = 180