Question

A ball thrown at aspeed 32 meter per second in 30 degree in horizontal direction the maximum heiht will attain

Answer 1

H=12.8m

Explanation:

1. u=32sin 30°=32/2=16
2. v^2=u^+2gH (v=0 ,g=10)
3. 0=16^2+2×10×H
4. H=256/20
5. H=12.8m