Physics, asked by suvosarkar1538, 8 hours ago

A ball thrown at aspeed 32 meter per second in 30 degree in horizontal direction the maximum heiht will attain

Answers

Answered by dtdasun365

0

H=12.8m

Explanation:

u=32sin 30°=32/2=16
v^2=u^+2gH (v=0 ,g=10)
0=16^2+2×10×H
H=256/20
H=12.8m

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