Question

A ball thrown horizontally from the top of a hill lands 17.0m from the base of the tower. If the speed at which the object was objected was 10.50m/s, how high is the hill?

Answer 1

Acceleration due to gravity is constant so we use equation of motion-

${v}^{2} - {u}^{2} = 2gs \\ taking \: positive \: axis \: downward \: direction \\ \\ {0}^{2} - {(10.5)}^{2} = 2(g)( - h) \\ 110.25 = 20h \\ h = \frac{110.25}{20} \\ h = 5.125m$