Question

A ball thrown up is caught by the thrower after 4 second how high did it go and with what velocity it thrown .How far was it below the highest point 3 second after it was thrown

Answer 1

Answer:

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Answer 2

Answer:

imitial velocity = 20m/s

max height=20 m

Explanation:

let inital velocity be u

we know,

t= 2u/g

hence,

4=2u/10

=> u=20 m/s

max height= u^2/2g

=> h= 20^2/2×10

=>h=20 m