Question

A ball thrown up is caught by the thrower after 4s. how high did it go and with what velocity was it thrown ? how far was it below the highest point 3s after it was thrown ? (g=9.8m/s2)

Answer 1

the time taken to move upward=time taken to move downwad
so the time taken by the stone to come down from the highest point=2 s
so from 2 nd equation of motuion,as it was moving down: 0+1/2 gt2=h
h=5x2x2=20 m
so ut-1/2 g t2=20 while moving up
2u-20=20
u=20m/s
ie the distance it covered in t=1 sec from the highest point:h=5t2=5m

Answer 2

Answer:

Answer is given above.