Abcd are four points in a plane such that abd and dbc form two triangles.area of abd is 10 units and area of adc is 20 units.what is the ratio of lengths(ad/dc)? i)points adc are collinear ii)db is 5 units long and is perpendicular to ac.
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base is common for both of the triangles
area(abd)/area(bdc)=10/20
=>(1/2)*bd*h1)/(1/2*bd*h2)=1/2
=>h1/h2=1/2
h1 and h2 are parallel (as they are perpendicular 2 same line)
from this we can say that,
respective angles are same for both the triangle.
so ,
ad/dc=1/2 (ans)
area(abd)/area(bdc)=10/20
=>(1/2)*bd*h1)/(1/2*bd*h2)=1/2
=>h1/h2=1/2
h1 and h2 are parallel (as they are perpendicular 2 same line)
from this we can say that,
respective angles are same for both the triangle.
so ,
ad/dc=1/2 (ans)
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