Question

A ball thrown up vertically returns to the thrower after 6
Find
(a) the velocity with which it was thrown up,
(b) the maximum height it reaches, and
(c) its position after 4 s.​

Answer 1

Answer:

a) 30 m/s

b) 45 m

c) 40 m

Explanation:

the ball will reach the top in 3s.

so by

v=u + at,

0=u-10(3)

so u=30 m/s

max height = 30(3) - 0.5(10)(9)= 90-45 = 45 m

4s is 1s after it reached the top.

s=0+0.5(10)(1)= 5 m

so height from ground is 40 m