Question

a ball thrown up vertically returns to the thrower after 8 sec find velocity , maximum height , position after 4 seconds

Answer 1

v = u +at

u =?

v=0

im taking a =10

t = 8sec

s =?

lets find u first

v=u+at

0=u+ -10*8

0=u +-80

-u=-80

u=80 m/s

now we found out u

2as=v^2-u^2

2*10*s=0^2- 80^2

20s=-6400

s= 320m

postion after 4sec

8/4=4

s= ut+1/2at^2

s=0+80

s= 80m