find the zeros of the following quadratic polynomials 6 x square - 3 - 7x
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2
the zeros are ( 3x+1),(2x-3)
hence X=-1/3,3/2
hence X=-1/3,3/2
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=>6x² -7x -3=0
=> 6x² -9x +2x -3 =0
=> 3x(2x-3) +1(2x-3)=0
=> (2x-3)(3x+1)=0
therefore , (2x-3) = 0 then x = 3/2
and. (3x+1)=0 then x = -1/3
=> 6x² -9x +2x -3 =0
=> 3x(2x-3) +1(2x-3)=0
=> (2x-3)(3x+1)=0
therefore , (2x-3) = 0 then x = 3/2
and. (3x+1)=0 then x = -1/3
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