Question

a ball thrown up vertically Rises to a height of 15 metres calculate the velocity with which the ball is thrown upwards and the time taken by the ball to reach the time taken to reach the highest point (g=10ms-2)​

Answer 1

Answer

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Distance travelled, s = 10 m

Final velocity, v = 0 m/s

g = -9.8 m/s2

1) Using,

v2−u2=2gs

u2=196

u=14m/s, where u is the velocity with which the object is thrown upwards.

2) Using,

v=u+gt

t=gv−u=1.43 sec

Answer 2

Answer:

Given parameters are

Initial velocity of the ball (u) = 49m/s.

The velocity of the ball at maximum height (v) = 0.

g = 9.8m/s2

Let us consider the time is t to reach the maximum height H.

Consider a formula,

2gH = v2 – u2

2 × (- 9.8) × H = 0 – (49)2

– 19.6 H = – 2401

H = 122.5 m

Now consider a formula,

v = u + g × t

0 = 49 + (- 9.8) × t

– 49 = – 9.8t

t = 5 sec

(1) The maximum height to which the ball rises = 122.5 m

(2) The total time ball takes to return to the surface of the earth = 5 + 5 = 10 sec.