A ball thrown up vertically upwards with a velocity of 45 m/sec, RETURNS back to the thrower in 6 sec. Assuming there is no air friction, plot a graph between velocity and time. From the graph calculate: 1. Declaration 2. Acceleration 3. The total distance covered by ball 4. The average velocity.
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ok, so first calculate the highest height and at what time attained by this ball
h= u*u/2g
so when the ball attains its max height, it's velocity becomes zero. again due to gravitational force the velocity gradually increases. so you should have the following graph.
deceleration is the acceleration of the ball while it's reaching the highest point and acceleration is the acceleration that the ball gains while coming back to the thrower. use Newton's laws of motion.
average velocity is zero since displacement is 0.
hope this helps. please ask me if you have any doubts.
h= u*u/2g
so when the ball attains its max height, it's velocity becomes zero. again due to gravitational force the velocity gradually increases. so you should have the following graph.
deceleration is the acceleration of the ball while it's reaching the highest point and acceleration is the acceleration that the ball gains while coming back to the thrower. use Newton's laws of motion.
average velocity is zero since displacement is 0.
hope this helps. please ask me if you have any doubts.
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