A ball thrown up with a speed of 0.5m/s . How long will it take to reach that height
Answers
Answered by
21
I think question should be “How long it takes to reach maximum height”
T = u / g
= 0.5 / 10
= 0.05 s
= 50 milliseconds
It takes 50 milliseconds to reach maximum height.
T = u / g
= 0.5 / 10
= 0.05 s
= 50 milliseconds
It takes 50 milliseconds to reach maximum height.
Answered by
23
V=u+gt
V=0m/a
U=0.5m/s
g=-10
0=0.5-(10.t)
-0.5=-10t
t=0.05
V=0m/a
U=0.5m/s
g=-10
0=0.5-(10.t)
-0.5=-10t
t=0.05
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