If the amount after 2 years at the rate of 6 percent per annum compounded annually is rs 12,000 find the principal.
Answers
Answered by
3
Here,
A = P*( 1+6/100 )² + P
12000 = P [ ( 106/100 )² + 1 ]
P = 12000/ [ ( 106/100 )² + 1 ]
= 5651 approx
A = P*( 1+6/100 )² + P
12000 = P [ ( 106/100 )² + 1 ]
P = 12000/ [ ( 106/100 )² + 1 ]
= 5651 approx
Answered by
23
Hi ,
Let the principal = P
amount ( A ) = Rs 12000
time ( T ) = 2 years
number of times of interest paid ( n ) = 2
rate of interest ( r ) = 6 %
we know that ,
A = P ( 1 + r / 100 )^n
12000 = P ( 1 + 6 / 100 )²
12000 = P ( 100 + 6 )² / ( 100 )²
12000 = P ( 106 / 100 )²
12000 = P ( 53 / 50 )²
12000 × ( 50 / 53 )² = P
( 12000 × 50 × 50 ) / ( 53 × 53 ) = P
10679.96 = P
P ≈ Rs 10679.96
I hope this helps you.
:)
Let the principal = P
amount ( A ) = Rs 12000
time ( T ) = 2 years
number of times of interest paid ( n ) = 2
rate of interest ( r ) = 6 %
we know that ,
A = P ( 1 + r / 100 )^n
12000 = P ( 1 + 6 / 100 )²
12000 = P ( 100 + 6 )² / ( 100 )²
12000 = P ( 106 / 100 )²
12000 = P ( 53 / 50 )²
12000 × ( 50 / 53 )² = P
( 12000 × 50 × 50 ) / ( 53 × 53 ) = P
10679.96 = P
P ≈ Rs 10679.96
I hope this helps you.
:)
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