Question

a ball thrown upwards takes 5s to reach the maximum height. Find (a) the initial speed with which it was thrown and (b) the maximum height reached

Answer 1

t = 4s v = 0m/s a = -9.8m/s

(a) According to Newton's first law of Motionv = u + at0 = u + (-9.8)(4)0 = u - 39.239.2 m/s = u


(b)According to Newton's second law of motion.s = ut + 1/2 * at2s = (39.2)(4) + 1/2 * (-9.8)(4)2s = 156.8 + 1/2 * (-156.8)s = 156.8 - 78.4s = 78.4 m
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