A ball thrown vertically up from the top of a tower reaches the ground in 12 s. Another ball thrown vertically downwards from the same position with the same speed takes 4 seconds to reach the ground. Find the height of the tower.
Take G =10 m/s^2
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Distance = ut + (1/2)at^2
Height of tower = distance for downward thrown ball
H = 4u + (1/2)10(4)^2
H = 4u + 5×16
H = 4u + 80
Out of 12 sec for upwards thrown ball 4 secs to go below tower and rest 8 secs half to go upward and half to come to tower peak again
So aftet 4 secs ball will be at its peak
Ball thrown up ward speed at top = 0
V = u + at
a = -g as going upward
0 = u + (-10)×4
u = 40 m/s
H = 4×40 + 80
H = 240m
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