A ball thrown vertically up with an initial velocity of 25 m/s. calculate the maximum altitude reached by the ball and the time t after throwing for it to return to the ground. Neglect air resistance and take the gravitational acceleration as 9.81 ms^-2.
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Answer:
31.9m
Explanation:
Formula for H maximum =u²/2g
H=25²/2x9.81
H=625/19.62=31.9m
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