Question

a ball thrown vertically upward with a speed of 9.6 metre per -1 from the top of the tower returns to the earth in 6 second calculate the height of the tower​

Answer 1

Explanation:

u=9.6 m/s

t=6s

a=-9.8m/s^2

s=h=?

h=ut+1/2at^2

h=9.6 ×6+1/2×-9.8 ×6^2

h=96 /10×6-1/2×98/10×36

h=288/5-882/5

h=-594/5

h=-118.8 m

distance never negative

so,

h=118.8 m