a ball thrown vertically upward with speed of 9.6 metre per second from the top of a tower return to the earth in 6 seconds find the heiht of Tower
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initial velocity, u = 9.6m/s
final velocity, v = 0 m/s
Time taken, t = 6 s
Acceleration due to gravity, a = -9.8 m/s^2
using second equation of motion,
distance (s) = ut+1/2gt^2
s = 9.6*6 + 1/2 *9.8*(6)^2
s = 234 m
Height of tower is 234 m
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