Question

A ball thrown vertically upward with velocity of 25m/s ? How high above the ground at 6 sec?

Answer 1

Answer:

4.16 m

Explanation:

distance = velocity / time

Answer 2

Answer:

Initial velocity (u)=0

Final velocity (v)=25m/s

a=(v-u)/t

=(25-0)/6

=25m/s^2/6

According to the equation of motion:

h=ut+1/2at^2

$=0×6+ \frac{1}{2} × \frac{25}{6} ×6^2$

$=\frac{1}{2} × \frac{25}{6} ×36$

=75m

But if you use direct Formula:

D=S×T

=25×6

=150m