A ball thrown vertically upwards reached a maximum height 20m. a) What was the velocity of the stone at the instant of throwing up? b) How much time did the ball take to reach the height 20m?
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The initial velocity of the projectile, u = 19.799 m/s
The time of flight of projectile to reach 20 m is, t = 2.02 s
Explanation:
Given data,
The maximum height of the projectile, h = 20 m
`The maximum height of the projectile thrown vertically upwards is given by the formula,
h = u²/2g
∴ u = √(2hg)
= √(2 x 20 x 9.8)
= 19.799 m/s
The initial velocity of the projectile, u = 19.799 m/s
The time of flight to reach 20 m height,
t = u / g
= 19.799 / 9.8
= 2.02 s
Hence, the time of flight of projectile to reach 20 m is, t = 2.02 s
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