Solve:
1/2x-3 > 1, x not= 2/3, x represents R
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Question:
Solve for "x" in the given inequation :
1/(2x-3) > 1 , x ≠ 2/3 , x € R.
Answer:
x € (3/2 , 2)
Solution:
We have;
=> 1/(2x-3) > 1
=> 1/(2x-3) - 1 > 0
=> {1 - (2x-3)}/(2x-3) > 0
=> (1-2x+3)/(2x-3) > 0
=> (4-2x)/(2x-3) > 0
=> 2(2-x)/(2x-3) > 0
=> (2-x)/(2x-3) > 0
=> -(x-2)/(2x-3) > 0
=> (x-2)/(2x-3) < 0
Now,
Two cases arises;
Case(1):
When (x-2) > 0 and (2x-3) < 0
=> x > 2 and 2x < 3
=> x > 2 and x < 3/2
{This case is not possible, as there exist no real number which is greater than 2 and smaller than 3/2 simultaneously.}
OR
Case (2):
When (x-2) < 0 and (2x-3) > 0
=> x < 2 and 2x > 3
=> x < 2 and x > 3/2
=> x € (3/2 , 2)
The solution set for the given inequation will be given as the union of case(1) and case(2).
Hence,
The solution set for the given inequation is : x € (3/2 , 2) .
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