Question

a ball thrown vertically upwards with a speed of 19.6ms^-1 from the top of the tower retyrns to the earth in 6 seconds . find the height of the tower.​

Answer 1

Answer:

59 m

Explanation:

Given that,

Initial velocity u=19.6m/s

Final velocity v=0

Time t=6sec

The acceleration is

We know that,

v=u+at

0=19.6+a×6

a=−3.26m/s

2

Now, the height is

From equation of motion

s=ut+

2

1

at

2

s=19.6×6−

2

1

×3.26×36

s=58.9

s=59m

Hence, the height of the tower is 59 m