Question

a ball thrown vetically up return to the thrower after 6 sec. find the velocity with which it jas thrown and maxximum height it reaches​

Answer 1

Answer: 30m/s and 45 m

Explanation: time of flight is given as 6s ,t=2u/g=6

                                                                        =u/g=3⇒u=3g=30m/s                              maximum height is h=u²/2g⇒900/20=45m