A ball vertically thrown upwards with a speed of 19.6m/s from the top of a tower returns to earth in 6s .find the height of the tower .by not using the equations of motion..
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Answer:
If ball is thrown upwards,
then it can be derived that,
H = - ut + at^2/2
(u= 19.6 m/s= 2g m/s)
Thus,
H = - 12g + 18g = 6g
Height of tower is 58.8 m
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