Question

a ball was dropped from a height of 25m.How many seconds before it hit the ground

Answer 1

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Answer 2

h = 25m

Acceleration due to gravity = g = 9.8m\s

u = 0m\s

Therefore,

s = ut + 1/2at²

25 = 0*t + 1/2*9.8*t²

t² = 50/9.8

t = √5.1

t = 2.2s

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