A ball weighing 10 g hits a hard surface with a speed of 5 m/s and rebound with the same speed .the ball remains in contact with the surface for 0.01 s the average force. exerted by the surface on the ball is
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Favg = change in movementum /time
F = 2*0.01*5/0.01=10N
F = 2*0.01*5/0.01=10N
Answered by
1
Answer:
10 N
Explanation:
Force = change in momentum / time
F = (mv - mu)/t
F = [1/100 ( 5 - (-5) ) ]/ (1/100) [in SI units]
F = 1/100 * 10 * 100
F = 10 N
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