Physics, asked by shourya8607, 9 days ago

A BALL WEIGHING 4KG OF DENSITY 4000kg/m³ is completely immersed In water of density 10³kg/m³ . Find the force of buoyancy on it​ [g = 10m/s²]


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Answers

Answered by rudransh4375
2

Answer:

10N

Explanation:

Buoyancy force can be calculated with the equation Fb = Vs ×D × g, where Fb is the buoyancy force, Vs is the submerged volume, D is the density of the fluid the object is submerged in, and g is the force of gravity.

In this case, the weight of the ball is 4 kg and the density of the ball is

4000kg/m^3. Therefore the volume is given as

v = m/d = 4/4000 m^ 3. Substituting the given values in the equation, we get,

Fb = V sDg = 4/4000m^ 3 × 1000kg/m^ 3 × 10m/s^ 2 = 10N

Hence, the force of buoyancy is 10 N.

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