A bus covers a certain distance in 42 minutes if it run at the speed of 50 km/hr what must be the speed of the bus in order to reduce the time of the journey to 30 minutes.
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Answer:
let distance = x km
formula of speed = distance/ time
time taken by bus the cover the distance =42/60
=7/10 hrs
distance = speed × time = 50 × 7/10 = 35 km
Now,
speed = distance/time
= 35/30/60
=35/30 × 60
= 70 km / hr
Step-by-step explanation:
this is a case of inverse variation
so more speed , less time
and
In Invese variation
product of the quantities remain same
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