A ball which is thrown upwards vertically return to the earth after 8second. Find
(I) initial velocity with which it is thrown up (II) maximum height it reaches
(III) it's position after 5seond
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Answer:
Explanation:
Here acceleration is gravity that is 10m/s^2
Let inital velocity is u
And final velocity at highest point is 0 and time is 8s
a=v-u/t
-10*8=0-u
-80=-u
u=80m/s
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