Question

A ball whose kinetic energy is e is thrown at an angle of 45

Answer 1

Kinetic energy E at the highest point = ½m(u/√2)2 = E/2

Explanation:

Correct statement:

A ball whose kinetic energy is E, is projected at an angle 45 degrees to the horizontal. Find the kinetic energy of the ball at the highest point of its flight?

Solution:

Kinetic Energy E = ½mv^2

• At the highest point, vertical component of velocity becomes zero
• Only the horizontal component is left

That is given by

ux = u cosθ

θ = 45°, so 

cosθ = 1/√2

ux = u/√2

Kinetic energy E at the highest point = ½m(u/√2)2 = E/2

Also learn more

A ball is thrown at a speed of 40 m/s at an angle of 60° with the horizontal. Find (a) the maximum height reached and(b) the range of the ball. Take g=10 m/s²?

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