Question

A ball with a mass m is falling on to the ground with some velocity v1 and raising with velocity v2 . find the impulse?

Answer 1

m = m
u = -v1 (they are in opposite direction)
v = v2
Impulse = m×(v - u)
= m×( v2 -(-v1))
= m×(v2+ v1)

so impulse = m (v1 + v2)

hope it helps plz mark as brainliest

Answer 2

GIVEN:-

▶initial velocity= -v1
{ as body is falling down}

▶final velocity= +v2
{ as body is going up}
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➡Impulse = change in momentum

=>Impulse= m∆v

=>Impulse= m(final velocity - initial velocity)

=>Impulse= m[v2-(-v1)]

=>Impulse= m(v2+v1)
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hope it helps you...
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