A ball with a mass m is falling on to the ground with some velocity v1 and raising with velocity v2 . find the impulse?
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Answered by
3
m = m
u = -v1 (they are in opposite direction)
v = v2
Impulse = m×(v - u)
= m×( v2 -(-v1))
= m×(v2+ v1)
so impulse = m (v1 + v2)
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u = -v1 (they are in opposite direction)
v = v2
Impulse = m×(v - u)
= m×( v2 -(-v1))
= m×(v2+ v1)
so impulse = m (v1 + v2)
hope it helps plz mark as brainliest
Answered by
0
GIVEN:-
▶initial velocity= -v1
{ as body is falling down}
▶final velocity= +v2
{ as body is going up}
________________________________
➡Impulse = change in momentum
=>Impulse= m∆v
=>Impulse= m(final velocity - initial velocity)
=>Impulse= m[v2-(-v1)]
=>Impulse= m(v2+v1)
________________________________
hope it helps you...
☺☺
▶initial velocity= -v1
{ as body is falling down}
▶final velocity= +v2
{ as body is going up}
________________________________
➡Impulse = change in momentum
=>Impulse= m∆v
=>Impulse= m(final velocity - initial velocity)
=>Impulse= m[v2-(-v1)]
=>Impulse= m(v2+v1)
________________________________
hope it helps you...
☺☺
Devipvu2004:
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