A balloon contain 1000kg of air. If its temperature is changed by 60 degree celsius then find change in thermal energy of air
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Hello dear,
● Answer-
∆E = 17.2×10^6 J
● Explanation-
# Given-
W = 1000 kg
∆T = 60° C = 60 K
# Solution-
As standard convention, molar mass of air is taken as 0.029 kg/mol.
No of moles of air in balloon-
n = 1000 / 0.029
n = 34483
Change in thermal energy of air is calculated by-
∆E = nR∆T
∆E = 34482 × 8.314 × 60
∆E = 17.2×10^6 J
Therefore, change in thermal energy of air is 17.2×10^6 J.
Hope this helps...
● Answer-
∆E = 17.2×10^6 J
● Explanation-
# Given-
W = 1000 kg
∆T = 60° C = 60 K
# Solution-
As standard convention, molar mass of air is taken as 0.029 kg/mol.
No of moles of air in balloon-
n = 1000 / 0.029
n = 34483
Change in thermal energy of air is calculated by-
∆E = nR∆T
∆E = 34482 × 8.314 × 60
∆E = 17.2×10^6 J
Therefore, change in thermal energy of air is 17.2×10^6 J.
Hope this helps...
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