A balloon filled with an ideal gas is taken from the surface of the sea deep to a depth of 100m. What will be its volume in term of its original volume
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The answer is as follows:
• Pressure at the sea level or surface=760mm Hg
• It translates into 1033.3 cm H20
• Thereafter, furthermore conversion results in 10.3m H20
• Pressure at a depth of 100m= 100+ 10/3=110.3m of H20
• Applying formula at constant temperature
• P1V1=P2V2
• P2 and V2 are the respective pressure and volume at 100 m depth
• V2= 0.093V1
• =9.3% of V1
• Pressure at the sea level or surface=760mm Hg
• It translates into 1033.3 cm H20
• Thereafter, furthermore conversion results in 10.3m H20
• Pressure at a depth of 100m= 100+ 10/3=110.3m of H20
• Applying formula at constant temperature
• P1V1=P2V2
• P2 and V2 are the respective pressure and volume at 100 m depth
• V2= 0.093V1
• =9.3% of V1
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