A balloon filled with helium raises to a certain height at which it gets fully inflated to a volume of 10^5 ltr.
If at this altitude temperature and atmospheric pressure is 268k and 2*10^-3atm respectively, what weight of helium is required to fully inflated the balloon?
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ইউফঅফওফঅয়এয়অ৷ওয় এয়অফঘএঅফ৷ফ এয়অ৷ও আখআউএয়ঈ এঘঅ৷ঐ এঘঅ৷ঐ আঈফঘঐ
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using PV=nRT formula
2×10^-3 × 10^5 = n× 8.314× 268
--> n = 0.1
--> weight=n× gram molecular weight of He
--》weigh=0.1×4 =0.4 grams.
2×10^-3 × 10^5 = n× 8.314× 268
--> n = 0.1
--> weight=n× gram molecular weight of He
--》weigh=0.1×4 =0.4 grams.
srinivasvenkat:
I think it will helpyou so!! -))
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