Question

A balloon has a mass of 5g in air the air escapes from the ballloon at an uniform rate with a velocity of 5cms^(-1) if the balloon shrinks completely in 2.5s find the average force acting on the balloon

Answer 1

F=m(v-u)/t
5(5-0)/2.5
25/2.5
10N

Answer 2

Hello buddy,

◆ Answer-
F = 10 dyne

◆ Explaination-
# Given-
m = 5 g
t = 2.5 s
v = 5 cm/s

# Solution-
Average force acting on the balloon is calculated by Newton's second law of motion.
F = mv/t
F = 5 × 5 / 2.5
F = 10 dyne
F = 10^-4 N

Therefore, average force acting on the balloon is 10 dyne.

*Note CGS units used here.

Hope this helps...