A balloon is ascending at the rate of 4.9m/s. A packet is dropped from the balloon when situated at a height of 245m.
How long does it take the packet to reach the ground?
What is its final velocity?
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Initially the packet was ascending up with the balloon.
Taking upward as positive direction; initial velocity, u = 4.9 m/s final velocity = v m/s initial height, h, = 245 m final height, h2 = 0 a = -9.8 m/s
time taken = t seconds
time taken = t seconds
s = ut + 0.5at^2
= (h2-h) = ut + 0.5at^2- 0-245
= 4.9t + 0.5*(-9.8)t^2245
= 4.9t - 4.9t^2
→ 4.9t^2 -4.9t -245 =0
Solving it, we get t= 7.59s
v= u + at = 4.9 -9.8x7.59 = 4.9 - 74.38
= -69.48 m/s
So velocity is 69.48 m/s downward
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