Question

A balloon is ascending with a velocity of 9.8ms^-1, a sand bag dropped from the balloon when it is at a height of 39.2m from the ground calculate the time taken by bag to reach the ground

Answer 1

Answer:

4s

Explanation:

velocity of bag,u=velocity of balloon in upward direction=9.8m/s

as soon as the bag is released 'g' acts in downward direction

now applying S=ut+1/2gt^2

-39.2=9.8t+1/2(-9.8)t^2(taking upward as +ve)

t^2-2t-8=o

on solving t=4,-2

accepting +ve value of t

so time taken by bag to reach ground=4s