A balloon is going upwards with velocity 12
m/sec. It releases a packet when it is at a
height of 65 m from the ground. How much
time the packet will take to reach the ground
(g=10m/sec)
1) 5 sec 2) 6 sec 3) 7 sec 4) 8 sec
Answers
Answered by
1
Answer:
a)5 seconds
Step-by-step explanation:
Given,
Take upward direction as -ve and downward direction as +ve.
u=−12m/s
h=65m
g=10m/s ^2
v=0m/s
From 2nd equation of motion,
h=ut+ 1/2 gt^2
65=−12t+ 1/2×10t^2
65=−12t+5t^2
5t^2−12t−65=0
5t(t−5)+13(t−5)=0
t−5=0,5t+13=0
t=− 13/5,5
Time taken to reach the ground is 5sec.
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