Question

The distance covered by the free falling body in two seconds is​

Answer 1

Answer:

The accelaration would be 9.8ms^-2 and the initial velocity would be 0. So in its starting 1 seconds it will travel 4.9 meters if we consider no air friction. So S = 0.5* 9.8*1^2 = 4.9meters

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Answer 2

Answer:

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