Question

A balloon is moving uoward with velocity 10 m/s. It releases a stone which comes down to the ground in 11 sec the height of the balloon from the ground at the moment when the stone was dropped is

Answer 1

Answer:

u

stone

=10m/s (initial velocity of stone)

t=11s

∴H=−ut+

2

1

gt

2

(H=height of baloon)

H=−10×11+

2

1

×10×121=605−110=495m