A bullet train is moving on a velocity of 180km/h and it takes 5sec to stop after brakes are applied .find the force exerted by the wheels of train if its mass with the wagon is 2000kg
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Answered by
13
here is your answer
given :
initial velocity (u) = 180 km/hr = 180*(5/18) = 50 m/s
final velocity (v) = 0
time taken (t) = 5 seconds
mass (m) = 2000kg
to find : force exerted
solution :
by using first equation of motion
v = u+at
0 = 50+5a
5a = -50
a = -50/5
a = -10 m/s²
now,
force = mass*acceleration
force = 2000*(-10)
force = -20000 Newton
so, the force exerted will be -20000 Newton
given :
initial velocity (u) = 180 km/hr = 180*(5/18) = 50 m/s
final velocity (v) = 0
time taken (t) = 5 seconds
mass (m) = 2000kg
to find : force exerted
solution :
by using first equation of motion
v = u+at
0 = 50+5a
5a = -50
a = -50/5
a = -10 m/s²
now,
force = mass*acceleration
force = 2000*(-10)
force = -20000 Newton
so, the force exerted will be -20000 Newton
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3
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