Question

A balloon is rising vertically up with a constant velocity. If releases a body when it was at a certain height above the ground. Find the separation distance between the body and the balloon after 4 seconds? $g=10m/s^2$ 1) 80 m 2) 120 m 3) 160 m 4) 180 m

Answer 1

Answer:

Step-by-step explanation:

Given,

u=10m/s in upward direction.

g=−10m/s

2

 in downward direction

t=3sec

H=45m

So by second equation of motion:

s=ut+

2

1

​

at

2

=10×3+

2

1

​

(−10)×3×3

=30−45

=−15m

Here negative sign indicates that it is directed downwards.

So height from the ground when he opened parachute is =45−15=30m